Given f(x)=2x2−5x−3 and g(x)=2x2+x .


What is (fg)(x) ?





−2x−3x where x≠0, −12


x−3x where x≠0, −12


x−2x−3 where x≠0, −32


xx−3 where x≠0, 3

Respuesta :

Answer:

For  (fg)(x)

(fg) (x) = 4x^4 - 8x^3 -11x^2  -3x

With no restrictions on the x

Step-by-step explanation:

To find (fg) (x) = f(x) . g(x)  

We need to multiply f(x) with g(x)

(fg) (x) = (2x^2 -5x -3) * (2x^2 + x)

fg(x) = 4x^4 + 2x^3  - 10x^3 - 5x^2 -6x^2 -3x

fg(x) = 4x^4 - 8x^3 -11x^2  -3x

Answer:

(fg)(x) = [tex]4x^{4}-8x^{3}-11x^{2}-3x[/tex] is the answer.

Step-by-step explanation:

It is given f(x) = 2x² - 5x -3 and g(x) = 2x² + x

Then we have to find (fg)(x)

As we know (fg)(x) = f(x).g(x)

By putting the values of f(x) and g(x)

(fg)(x) = (2x² - 5x - 3)(2x²+x)

         = 2x²(2x²+x) - 5x(2x² + x) - 3(2x² + x)

         = [tex]4x^{4}+2x^{3}-10x^{3}-5x^{2}-6x^{2}-3x[/tex]

         = [tex]4x^{4}-8x^{3}-11x^{2}-3x[/tex]

So the value of (fg)(x) = [tex]4x^{4}-8x^{3}-11x^{2}-3x[/tex] is the answer.