Answer:Total number of chocolates
9+3+6 = 18
The probability that she chose a MC is the number of Mc in the box of chocolate divided by the total number of chocolates
9/18
The probability that she chose a DC from the box is
3/18 = 1/6
Answer: Our required probability is 0.83.
Step-by-step explanation:
Number of milk chocolates = 5
Number of dark chocolates = 7
Number of peanut among milk chocolate = 4
Number of peanut among dark chocolate = 1
We need to find the probability that .It is a milk chocolate or has peanuts inside.
P(Milk chocolate) + P(peanut)
[tex]\dfrac{5}{12}+\dfrac{5}{12}\\\\=\dfrac{10}{12}\\\\=0.83[/tex]
Hence, our required probability is 0.83.
