Respuesta :
Answer:
x-intercept of f(x) is 0
x-intercept of g(x) is -1
g(x) is the image of f(x) after translate it 1 unit to the left
Step-by-step explanation:
In the graph f(x) = x²
The x-intercept = 0 ⇒ ∵ f(x) = 0 ⇒ ∴ x² = 0 ⇒ x = 0
The vertex of the parabola is (0 , 0)
In the graph g(x) = (x + 1)²
The x-intercept = 0 ⇒ ∵ g(x) = 0 ⇒ ∴ (x + 1)² = 0
x + 1 = 0 ⇒ x = -1
The vertex of the parabola is (-1 , 0)
∴ g(x) is the image of f(x) after translate it 1 unit to the left
Answer:
x-intercept of f(x) is 0
x-intercept of g(x) is -1.g(x) comes from the base function f(x) when it moves 1 unit to left.
Step-by-step explanation:
We have given two graphes.
We have to compare the x-intercept of the graphes.
As f(x) = x²
And g(x) = (x+1)²
put f(x)= 0 we have,
f(x) = x² = 0
x=0 (x-intercept)
Put g(x) = 0 then,
g(x) = (x+1)² = 0
(x+1) = 0
x= -1 (x-intercept)
The vertex of the parabola f(x) is (0,0).
And the vertex of parabola g(x) is (-1,0).
g(x) comes from the base function f(x) when it moves 1 unit to left.