What is the sine of angle x ?

Answer: [tex]sinx=\frac{b}{c}[/tex]
Step-by-step explanation:
By definition you have that:
[tex]sin\alpha=\frac{opposite}{hypotenuse}[/tex]
Based on the figure attached in the problem you have that:
[tex]\alpha=x\\opposite=b\\hypotenuse=c[/tex]
Therefore, you must substitute the above into [tex]sin\alpha=\frac{opposite}{hypotenuse}[/tex]
Then, the answer is:
[tex]sinx=\frac{b}{c}[/tex]
The answer is: [tex]sin(x)=\frac{b}{c}[/tex]
Since it's a right triangle, we can determine the Sine of the angle "x" using the following formula:
[tex]sin(x)=\frac{b}{c}[/tex]
Where:
[tex]b=opposite\\a=hypotenuse[/tex]
Also, we can determine the cosine and the tangent of the same angle "x" using the following formulas:
[tex]cos(x)=\frac{a}{c} \\tan(x)=\frac{b}{a}[/tex]
Where:
[tex]a=hypotenuse\\b=opposite\\c=adjacent[/tex]
Have a nice day!