Answer:
[tex]x^2 + y^2 -2ax -2by -a^2-b^2 -m^2 = 0[/tex]
Step-by-step explanation:
The vertex form of an equation is [tex](x-h)^2 + (y-k)^2 = r^2[/tex] and it has a center (h,k) and radius r which forms it. To write the general form, start with the vertex form and expand it out.
Here the center is (a,b) so h=a and k=b. Substitute these values with the radius r = m.
[tex](x-a)^2 + (y-b)^2 = m^2[/tex]
Expand out the exponents.
[tex]x^2 -ax -ax -a^2 + y^2 - by - by - b^2 = m^2\\x^2 -2ax -a^2 + y^2 -2by -b^2 = m^2\\x^2 + y^2 -2ax -2by -a^2-b^2 -m^2 = 0[/tex]
