Answer:
see explanation
Step-by-step explanation:
Given
2x² + 4 = - 5x + 1
To express in standard form subtract - 5x + 1 from both sides
2x² + 5x + 3 = 0 ← in standard form
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 + 3 = 6 and sum = + 5
The factors are + 2 and + 3
Use these factors to split the x- term
2x² + 2x + 3x + 3 = 0 ( factor the first/second and third/fourth terms )
2x(x + 1) + 3(x + 1) = 0 ← factor out (x + 1)
(x + 1)(2x + 3) = 0
Equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - [tex]\frac{3}{2}[/tex]
Answer:
x=3/2,1
Step-by-step explanation:
(Ignore the A's in the equation i couldn't find a way to get rid of them
Example of what im taliking about -[tex]±[/tex] the A ignore this)
Move all terms to the left side of the equation and simplify.
[tex]2x^2-5x+3=0[/tex]
Use the quadratic formula to find the solutions.
[tex]\frac{-b±\sqrt[]{b^2-4(ac)} }{2a}[/tex]
Substitute the values a=2
, b=−5, and c=3 into the quadratic formula and solve for x
[tex]\frac{5±\sqrt{b^2 - 4 (ac)} }{2a}[/tex]
Simplify.
[tex]x=\frac{5±1}{4}[/tex]
The final answer is the combination of both solutions.[tex]±[/tex]
x=32,1[tex]x= \frac{3}{2} ,1[/tex]
Hopefully this helps ^.^
