Answer:
54
$3 dollar coupons were given
Step-by-step explanation:
We can represent this question as a system of equations
Let
x = number of $1 dollar coupons
y = number of $3 dollar coupons
z = number of $5 dollar coupons
Twice as many $1 coupons were given out as $3 coupons,
x = 2*y
3 times as many $3 coupons were given as $5 coupons.
y = 3*z
The total value of all the coupons given out was $360
x*$1 + y*$3 + z*$5 = $ 360
The system results
x - 2y + 0 = 0 (1)
0 + y - 3z = 0 (2)
x + 3*y +5*z = $ 360 (3)
We substitute equation (2) and (1) into (3)
(2y) + 3*y + 5*(y/3) = $ 360
20*y/3 = 360
y = 54
