The combined area of the 3 windowpanes and frame shown below is 924 inches squared. The frame is of uniform width. What is the side length, x, of each square windowpane?

Answer:
The sides length x of each square windowpane is [tex]10\ in[/tex]
Step-by-step explanation:
we know that
[tex]924\ in^{2}=(6+3x+6)(6+x+6)\\ \\924=(12+3x)(12+x)\\ \\924=144+12x+36x+3x^{2}\\ \\ 3x^{2}+48x- 780=0[/tex]
Solve the quadratic equation
using a graphing tool
The solution is [tex]x=10\ in[/tex]
see the attached figure
Answer:
10 inches is the side length of each square windowpane.
Step-by-step explanation:
Length of the single window plane = x
Width of the single window plane = x
On combining all the windows pane ,length becomes , l= 3x
On combining all the windows pane ,width becomes , b= x
Length of the frame = L = 6 + 3x+ 6 = 12 + 3x
Width of the frame = B = 6 + x+ 6 = 12 + x
Area of the frame, A = L × B = [tex](12+3x)\times (12+x)[/tex]
Given sum of combined area of the 3 windowpanes and frame = [tex]924 inch^2[/tex]
[tex]a + A=924[/tex]
[tex](12+3x)\times (12+x)=924[/tex]
[tex]144+48x+3x^2=924[/tex]
[tex]3x^2+48x-780=[/tex]
[tex]x^2+16x-260=0[/tex]
[tex]x^2+26x-10x-260=0[/tex]
[tex]x(x+26)-10(x+26)=0[/tex]
[tex](x+260)(x-10)=0[/tex]
x = 10 (accept)
x = -26 (reject)
10 inches is the side length of each square windowpane.