Answer:
C
Step-by-step explanation:
Consider the trinomial [tex]3x^2+10x-8.[/tex]
We can rewrite it as
[tex]3x^2+10x-8=3x^2+12x-2x-8.[/tex]
Now group first two terms and last two terms:
[tex](3x^2+12x)+(-2x-8).[/tex]
The common factor in first two terms is [tex]3x[/tex] and the common factor in last two terms is [tex]-2.[/tex] Use the distributive property for both groups of terms:
[tex]3x^2+12x=3x(x+4),\\ \\(-2x-8)=-2(x+4),[/tex]
so
[tex](3x^2+12x)+(-2x-8)=3x(x+4)-2(x+4).[/tex]
Now you can see that [tex](x+4)[/tex] is a common factor, thus
[tex]3x(x+4)-2(x+4)=(x+4)(3x-2)=(3x-2)(x+4).[/tex]
Since the trinomial can be represented as a product of binomials, this trinomial is not prime.
