Answer:
[tex]\large\boxed{y=\dfrac{1}{4}x+2}[/tex]
Step-by-step explanation:
The slope-intercept form of the equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept → (0, b)
The point-slope form of the equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point
We have the equation of a line:
[tex]y-4=\dfrac{1}{4}(x-8)\to m=\dfrac{1}{4}[/tex]
and the point (0, 2) → b = 2.
Substitute:
[tex]y=\dfrac{1}{4}x+2[/tex]
