Answer:
The function intersects the y-axis at point (0.9) (vertex)
Step-by-step explanation:
we know that
The equation of a vertical parabola into vertex form is equal to
[tex]y=a(x-h)^{2}+k[/tex]
where
(h,k) is the vertex of the parabola
if a>0 then the parabola open upward (vertex is a minimum)
In this problem we have
[tex]y-x^2=9[/tex] -----> [tex]y=x^2+9[/tex]
This is a vertical parabola open upward
The vertex is the point (0,9)
The vertex is a minimum
see the attached figure to better understand the problem
The graph does not intersect the x-axis (the function has no real roots)
The function intersects the y-axis at point (0.9) (vertex)
