Answer:
2. +0.2 C
Explanation:
When the two spheres touch, the total charge will be redistributed such that the two spheres are at same potential:
[tex]V_1 = V_2[/tex]
The potential can be rewritten as ratio between the charge on the sphere (Q) and the capacitance of the sphere (C):
[tex]\frac{Q_1}{C_1}=\frac{Q_2}{C_2}[/tex]
Since the two spheres are identical, they have same capacitance:
[tex]C_1 =C_2=C[/tex]
So we can write
[tex]\frac{Q_1}{C}=\frac{Q_2}{C}[/tex]
[tex]Q_1=Q_2[/tex]
And since the total charge is
[tex]Q=+0.6 C-0.2 C=+0.4 C[/tex]
And this charge will be redistributed equally on the two spheres ([tex]Q_1 = Q_2[/tex]), we have
[tex]Q_1 = Q_2 = \frac{Q}{2}=\frac{+0.4 C}{2}=+0.2 C[/tex]
The resulting charge on the first sphere is mathematically given as
Q1=+0.2 C
Question Parameter(s):
Two identical spheres carry charges of +0.6 coulomb and -0.2 coulomb,
Generally, the equation for theratio between the charge on the sphere and the capacitance of the sphere is mathematically given as
Q1/C1=Q2/C2
Where
C1=C2
Therefore
Q_1=Q_2
Hence, Total charge
Q=+0.6 C-0.2 C
Q=+0.4 C
In conclusion, With redistribution equal on the two spheres
Q_1 = Q_2
Q1= Q/2
[tex]Q_1=\frac{+0.4 C}{2}[/tex]
Q1=+0.2 C
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