Answer:
Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to increase by 3.0 times.
Explanation:
So, for two different values of both P and V:
∴ P₁V₁ = P₂V₂.
∵ V₂ = 1/3V₁
∴ P₂ = P₁V₁/V₂ = P₁V₁/(1/3V₁) = 3P₁.