Answer:
3(NH₄)₂SO₄(aq) + 2Cr(NO₃)₃(aq) → 6NH₄NO₃(aq) + Cr₂(SO₄)₃(s)↓
Explanation:
3(NH₄)₂SO₄(aq) + 2Cr(NO₃)₃(aq) → 6NH₄NO₃(aq) + Cr₂(SO₄)₃(s)↓
3.0 moles of ammonium sulfate reacts with 2.0 moles of chromium(III) nitrate, forming 6.0 moles of ammonium nitrate and 1.0 mole of chromium(III) sulfate.