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What is the primary outgoing radiation put off by the earth?

A. ultra-violet (UV)

B. visible light

C. infrared (IR)

D. all of the above
Please help ASAP!!! :(

Respuesta :

C) Infrared.

Explanation

The wavelength of the "primary" (a.k.a. "peak") outgoing radiation from the earth depends on the surface temperature of the earth.

[tex]\displaystyle \lambda_\text{peak} = \frac{0.00289}{T}[/tex],

where

  • [tex]\lambda_\text{peak}[/tex] is the peak wavelength (in meters) of the outgoing radiation, and
  • [tex]T[/tex] is the absolute temperature of the earth (the one in degrees Kelvins.)

The average temperature on the earth is around 15 °C (around 60 °F.)

Convert to degrees Kelvins:

[tex]T = 15\;\textdegree\text{C} = (15 + 273.15)\;\text{K} = 288.15\;\text{K}[/tex].

Peak wavelength:

[tex]\displaystyle \lambda_\text{peak} = \frac{0.00289}{288.15} = 1.00\times 10^{-5} \;\text{m} = 1000\;\text{nm}[/tex].

What kind of electromagnetic radiation is that? Refer to a chart of the EM spectrum.

Radiations:

  • [tex]\lambda < 400\;\text{nm}[/tex]: ultra-violet (UV) or radiations that are more energetic than UV;
  • [tex]400\;\text{nm}<\lambda<700\;\text{nm}[/tex]: visible light;
  • [tex]\lambda > 700\;\text{nm}[/tex]: infrared (IR) and less energetic radiations.

[tex]\lambda \approx 1000\;\text{nm}[/tex] is longer than the wavelength of visible light. The radiation is infrared (IR.)

The answer is C. If you need any help let me know. :)