contestada

In how many ways committee of 8 people can be chosen out of 10 men and 6 women if there needs to be at least 5 women?

Respuesta :

Answer:

765

Step-by-step explanation:

Given in the question,

number of people to be choose with at least 5 women in it = 8

There are 2 ways to choose 8 members

1)

5 women

(6C5)(10C3)

6x120

720

2)

6 women

(6C6)(10C2)

1x45

45

Our final answer is 720 + 45 = 765 ways

Formula to calculate

nCr = n! / r!(n-r)!

The selection of members of the committee is an illustration of combination.

The number of ways of selection is 765

The given parameters are:

[tex]\mathbf{Men = 10}[/tex]

[tex]\mathbf{Women = 6}[/tex]

At least 5 women means that:

  • There are 5 women and 1 man in the committee or
  • There are 6 women and no man in the committee

So, the possible selection is:

[tex]\mathbf{Selection = ^6C_5 \times ^{10}C_3 + ^6C_6 \times ^{10}C_2}[/tex]

Apply combination formula

[tex]\mathbf{Selection = \frac{6!}{5!1!} \times \frac{10!}{7!3!} + \frac{6!}{6!0!} \times \frac{10!}{8!2!}}[/tex]

[tex]\mathbf{Selection = 6 \times 120 + 1 \times 45}[/tex]

[tex]\mathbf{Selection = 720 + 45}[/tex]

[tex]\mathbf{Selection = 765}[/tex]

Hence, the number of ways of selection is 765

Read more about selections and combinations at:

https://brainly.com/question/13387529