What is the force, in units of femtoNewtons, on an electron moving at a velocity of 7.26 x 106 ms-1 perpendicularly to a magnetic field when the magnetic flux density of 0.049 T?

Answer:
56.9 fN
Explanation:
The force exerted on the electron is:
[tex]F=Bqv[/tex]
where
B is the magnetic field strength
q is the electron's charged
v is the speed of the electron
In our problem,
B = 0.049 T
[tex]q=1.6\cdot 10^{-19} C[/tex]
[tex]v=7.26\cdot 10^6 m/s[/tex]
Therefore, the force is
[tex]F=(0.049 T)(1.6\cdot 10^{-19} C)(7.26\cdot 10^6 m/s)=5.69\cdot 10^{-14} N=56.9 fN[/tex]