Answer:
160 mN
Explanation:
The force exerted on the wire is given by
[tex]F=BIL sin \theta[/tex]
where
B is the magnetic field strength
I is the current in the wire
L is the length of the piece of wire
[tex]\theta[/tex] is the angle between the direction of the field and the wire
In this problem:
B = 0.97 T
I = 4.7 A
L = 3.5 cm = 0.035 m
[tex]\theta=90^{\circ}[/tex]
Therefore, the force exerted on the wire is
[tex]F=(0.97 T)(4.7 A)(0.035 m)(sin 90^{\circ})=0.160 N=160 mN[/tex]
