Answer:
Step-by-step explanation:
[tex]3x^2-9x-12=0\qquad\text{divide both sides by 3}\\\\\dfrac{3x^2}{3}-\dfrac{9x}{3}-\dfrac{12}{3}=\dfrac{0}{3}\\\\x^2-3x-4=0\\\\x^2+x-4x-4=0\\\\x(x+1)-4(x+1)=0\\\\(x+1)(x-4)=0\iff x+1=0\ \vee\ x-4=0\\\\x+1=0\qquad\text{subtract 1 from both sides}\\x=-1\\\\x-4=0\qquad\text{add 4 to both sides}\\x=4[/tex]
Answer:
Smaller x = -1
Larger x = 4
Step-by-step explanation:
