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Two object accumulated a charge of 4.5 μC and another a charge of 2. 8 μC. These two objects are separated by a distance of 2.5 cm. Calculate the magnitude of the electric force between these two objects.

181 .24 N

4.53 N

1.81 x 1014 N

2.02 x 10-8 N

Respuesta :

Answer:

We will use the Coulomb’s Law:

[tex]F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}[/tex]

[tex]\epsilon_0 = 8.85\times 10^{-12}[/tex]

[tex]F = \frac{1}{4 \times (3.14) \times (8.85\times 10^{-12})}\frac{4.5\times 10^{-6} \times 2.8 \times 10^{-6}}{(2.5\times 10^{-2})^2} = 181.24 N[/tex]

The answer is (a).

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