Answer:
b. 4
Explanation:
The electric force between two charged objects is given by:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the separation between the two objects
In this problem, we have that the charge of one object is quadrupled:
[tex]q_1'=4q_1[/tex]
while all the rest remain unchanged. So the new electric force between the two objects is
[tex]F'=k\frac{q_1' q_2}{r^2}=k\frac{(4q_1) q_2}{r^2}=4 k\frac{q_1 q_2}{r^2}=4F[/tex]
So, the force will quadruple as well.
