Given a square with side lengths represented by the function f(x)=2x+5, find the square.
A. 2x^2+10x+25
B. 4x^2+20x+25
C. 4x^2+20x+10
D. 2x^2+5x+10

Respuesta :

Answer:

[tex]B. 4x^2+20x+25[/tex]

Step-by-step explanation:

The length of the side:

[tex]2x+5[/tex]

In a square all sides have the same length.

And the area of a square is given by the formula:

[tex]Area=(length)^2[/tex]

so, substituting that the length is [tex]2x+5[/tex]

[tex]Area=(2x+5)^2[/tex]

and we solve this squared binomial with the formula:

[tex](a+b)^2=a^2+2ab+b^2[/tex]

in this case [tex]a=2x[/tex] and [tex]b=5[/tex]

thus, we get:

[tex]Area= (2x)^2+2(2x)(5)+(5)^2[/tex]

and solving:

[tex]Area=4x^2+20x+25[/tex]

which is option B.

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