Please help me out on this question I been stuck on it

Answer:
B, C
Step-by-step explanation:
[tex] x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]
[tex] x = \dfrac{-3 \pm \sqrt{3^2 - 4(1)(-5)}}{2(1)} [/tex]
[tex] x = \dfrac{-3 \pm \sqrt{9 + 20}}{2} [/tex]
[tex] x = \dfrac{-3 \pm \sqrt{29}}{2} [/tex]
Answer: B, C