wth is the value of b my guy
triangle ABC is a right triangle and cos (22.6°)=b/13. Solve for b and round the the nearest whole number.
which equation correctly uses thw value of b to solve for a?
tan(22.6)=a/13
tan (22.6)=13/a
tamd(22.6)=a/12
tan(22.6) =12/a

Respuesta :

Answer:

1) [tex]b=12[/tex]

2) [tex]tan(22.6\°)=\frac{a}{12}[/tex] (Third option)

Step-by-step explanation:

Remember that:

[tex]cos\alpha=\frac{adjacent}{hypotenuse}\\\\tan\alpha=\frac{opposite}{adjacent}[/tex]

1) Given that:

[tex]cos(22.6\°)=\frac{b}{13}[/tex]

You know that b is the adjacent side of the right triangle.

To solve for b you must multiply both sides of the expression by 13. Then, the value of b is:

[tex]13*cos(22.6\°)=\frac{b}{13}*13\\13*cos(22.6\°)=b\\b=12[/tex]

2) Then, you have that the equation correctly uses the value of b  ( adjacent side) to solve for a (opposite side) is:

[tex]tan(22.6\°)=\frac{a}{12}[/tex]

The value for b is 12 and  [tex]tan(22.6 ^{\circ \:} )=\frac{a}{12}\\[/tex].

RIGHT TRIANGLE

A triangle is classified as a right triangle when it presents one of your angles equal to 90º.  

For solving this question, you need to apply trigonometric ratios for the right triangle.

This question informs [tex]cos (22.6)=\frac{b}{13}[/tex]. Here, you should remember that cos of an angle is calculated by the ratio between the adjacent side from the angle and the hypotenuse of the right triangle. Therefore, [tex]cos=\frac{adj}{hyp}[/tex].

From a calculator, you find cos(22.6°)=0.92321. Thus,

                                       [tex]cos (22.6)=\frac{b}{13}\\ \\ 0.92321=\frac{b}{13}\\ \\ b= 0.92321*13\\ \\ b=12.002\\ \\ b=12[/tex]

The second part of question asks how to find the tangent value. The tangent can be calculated by formula presented below:

                               [tex]tan(\alpha )=\frac{opposite \;side\;angle}{adjacent\;side\;angle}[/tex]

For the angle 22.6°, you have:

  • opposite side = b=12
  • adjacent side= a
  • hypotenuse=13

Therefore,  [tex]tan(22.6 ^{\circ \:} )=\frac{a}{12}\\[/tex]

Learn more about the trigonometric ratios here:

brainly.com/question/11967894