Answer:
[tex]4.7\cdot 10^6 Pa[/tex]
Explanation:
The total force exerted by the man on the chair is equal to his weight:
[tex]F=W=mg[/tex]
where m=95.0 kg is the man's mass and g=9.8 m/s^2. Substituting,
[tex]F=(95.0 kg)(9.8 m/s^2)=931 N[/tex]
Since there are 4 legs, we can assume that the force is equally distributed over the 4 legs; so the force supported by each leg is
[tex]F=\frac{931 N}{4}=232.8 N[/tex]
The radius of each leg is [tex]r=0.400 cm=0.004 m^2[/tex], so the area of each leg is
[tex]A=\pi r^2 = \pi (0.004 m)^2=5\cdot 10^{-5} m^2[/tex]
And the pressure exerted on each leg is equal to the ratio between the force supported by each leg and the area:
[tex]p=\frac{F}{A}=\frac{232.8 N}{5\cdot 10^{-5} m^2}=4.7\cdot 10^6 Pa[/tex]
