Answer:
The ball experiences the greater momentum change
Explanation:
The momentum change of each object is given by:
[tex]\Delta p = m \Delta v= m (v-u)[/tex]
where
m is the mass of the object
v is the final velocity
u is the initial velocity
Both objects have same mass m and same initial velocity u. So we have:
- For the ball, the final velocity is
[tex]v=-u[/tex]
Since it bounces back (so, opposite direction --> negative sign) with same speed (so, the magnitude of the final velocity is still u). So the change in momentum is
[tex]\Delta p=m(v-u)=m((-u)-u)=-2mu[/tex]
- For the clay, the final velocity is
[tex]v=0[/tex]
since it sticks to the wall. So, the change in momentum is
[tex]\Delta p = m(v-u)=m(0-u)=-mu[/tex]
So we see that the greater momentum change (in magnitude) is experienced by the ball.
The ball has more momentum as compared to clay due to its higher motion.
The ball experiences the greater momentum change because it bouce back by the wall with the same amount of force while on the other hand, the clay sticks to the wall and stopped its motion
So we can conclude that the ball has more momentum as compared to clay due to its higher motion.
Learn more about momentum here: https://brainly.com/question/402617
