Answer:
2.41 L
Explanation:
We can solve the problem by using the ideal gas equation, which can be rewritten as:
[tex]\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}[/tex]
where we have:
[tex]p_1 = 1.01\cdot 10^5 Pa[/tex] (initial pressure is stp pressure)
[tex]V_1 = 746 mL = 0.746 L = 7.46\cdot 10^{-4}m^3[/tex] is the initial volume
[tex]T_1 = 0^{\circ}=273 K[/tex] is the initial temperature (stp temperature)
[tex]p_2 = 368 torr = 4.9\cdot 10^4 Pa[/tex] is the final pressure
[tex]V_2 = ?[/tex] is the final volume
[tex]T=155^{\circ}=428 K[/tex] is the final temperature
By substituting the numbers inside the formula and solving for V2, we find the final volume:
[tex]V_2 = \frac{p_1 V_1 T_2}{T_1 p_2}=\frac{(1.01\cdot 10^5 Pa)(7.46\cdot 10^{-4} m^3)(428 K)}{(273 K)(4.9\cdot 10^4 Pa)}=2.41\cdot 10^{-3} m^3[/tex]
which corresponds to 2.41 L.
