Answer:
= 664.10 mmHg
Explanation:
According to pressure law the pressure of a fixed mass of a gas is directly proportional to the absolute temperature.
Therefore;
P1/T1 = P2/V2
Standard temperature is equal to 0°C, which is 273.15 K.
In this case;
P1/T1= P2/T2
P1 = 778 mmHg
T1 = 47.0 + 273 K
= 320 K
P2 = ?
T2 = 0° C = 273.15 K
P2 =P1T2/T1
= (778 × 273.15)/320 K
= 664.10 mmHg
