For this case we must evaluate the following quadratic equation, [tex]y = -x ^ 2 + 3,[/tex] for [tex]x = -3[/tex], [tex]x = 0[/tex]and [tex]x = 3[/tex]
For [tex]x = -3[/tex]:
[tex]y = - (- 3) ^ 2 + 3\\y = -9 + 3 =\\y = -6[/tex]
For [tex]x = 0[/tex]:
[tex]y = - (0) ^ 2 + 3\\y = 0 + 3\\y = 3[/tex]
For [tex]x = 3[/tex]:
[tex]y = - (3) ^ 2 + 3\\y = -9 + 3\\y = -6[/tex]
Answer:
[tex](-3, -6)\\(0,3)\\(3, -6)[/tex]
