Answer:
8y^3 + 6y^2 - 29y + 15
Step-by-step explanation:
8y^3 + 12y^2 - 20y - 6y^2 - 9y + 15
then
8y^3 + 6y^2 - 29y + 15 is the product
Best regards
=8y^3+6y^2−29y+15
(4y−3)(2y^2+3y−5)
=(4y+−3)(2y^2+3y+−5)
=(4y)(2y^2)+(4y)(3y)+(4y)(−5)+(−3)(2y^2)+(−3)(3y)+(−3)(−5)
=8y^3+12y^2−20^y−6y^2−9y+15
