Answer:
[tex](-11,0)[/tex] and [tex](11,0)[/tex].
Step-by-step explanation:
The given ellipse has the equation:
[tex]\frac{x^2}{121}+\frac{y^2}{1}=1[/tex]
This can be rewritten as
[tex]\frac{x^2}{11^2}+\frac{y^2}{1^2}=1[/tex]
We compare this to the general equation of the ellipse:
[tex]\frac{x^2}{a^2}+\frac{y^2}{b^2}=1[/tex]
We have [tex]a=11[/tex] and [tex]b=1[/tex]
The vertices of this ellipse are at [tex](-a,0)[/tex] and [tex](+a,0)[/tex].
Therefore the vertices of this ellipse are at [tex](-11,0)[/tex] and [tex](11,0)[/tex].
The correct choice is A.
