Answer:
one solution: (0, –1)
Step-by-step explanation:
we have
[tex]y=5x-1[/tex] ----> equation A
[tex]-15x-3y=3[/tex] ----> equation B
isolate the variable y in the equation B
[tex]3y=-15x-3[/tex]
[tex]y=-5x-1[/tex] ----> equation C
Compare equation A and equation C
The equations are different
The slopes are different ( are not parallel lines)
therefore
The system has one solution
Solve the system
equate the equation A and equation C and solve for x
[tex]5x-1=-5x-1[/tex]
[tex]5x+5x=-1+1[/tex]
[tex]x=0[/tex]
Find the value of y
[tex]y=5(0)-1=-1[/tex]
The solution is the point (0,-1)
