Answer:
[tex]1.01\cdot 10^8[/tex] vibrations per second
Explanation:
The frequency of a wave corresponds to the number of vibrations per second:
[tex]f=\frac{N}{1 s}[/tex] (1)
where N is the number of vibrations per second.
In this problem, the frequency of the radio wave is
[tex]f=101 MHz =1.01\cdot 10^8 Hz[/tex]
And substituting into eq.(1), we find N:
[tex]N=f \cdot (1 s)=1.01\cdot 10^8[/tex]
