Answer:
[tex]1.33\Omega[/tex]
Explanation:
The equivalent resistance of three resistors connected in parallel is given by:
[tex]\frac{1}{R_T} = \frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}[/tex]
where in this problem we have
[tex]R_1 = 4.0\Omega[/tex]
[tex]R_2 = 3.0 \Omega[/tex]
[tex]R_3 = 6.0 \Omega[/tex]
Substituting into the equation, we find
[tex]\frac{1}{R_T} = \frac{1}{4.0\Omega}+\frac{1}{3.0\Omega}+\frac{1}{6.0\Omega}=0.75\Omega^{-1}[/tex]
And so, the equivalent resistance is
[tex]R_T=\frac{1}{0.75 \Omega^{-1}}=1.33\Omega[/tex]
