Respuesta :

ellyng10

Answer: Yes, Atoine is correct.

Step-by-step explanation:

The roots of a quadratic function are also known as the solutions or the zeros of a function. Here is how we get them:

1. Let y=0 to find the x-intercept(s).

0=x^2+25

2. Subtract 25 from both sides.

−25=x&2

3. Take the square root of both sides.

±√−25

=x

4. Simplify √−25​​​ to √​25​​​ı.

±√​25​​​ı=x

5. Since 5×5=25, the square root of 25 is 5.

±5ı=x

6. Switch sides.

x=±5ı

The equation above is not a real solution that represents a line.

Therefore, there are no x-intercepts.

In the given statement is "true".

Quadratic function:

[tex]\to f(x)=x^2+25[/tex]

  • Assuming "solution" refers to a real solution (it often does), then yes, he would be correct.
  • However, there are complex solutions to the equation.
  • Let's try to find the solution ourselves to understand the problem better:

            [tex]\to x^2+25=0\\\\\to x^2= -25\\\\\to x= \pm i\sqrt{25}\\\\[/tex]

   Since[tex]\sqrt{-25}[/tex] is an imaginary number then

           [tex]\to x=\pm 5i\\\\\to \sqrt{25}= 5[/tex]

Its equation's solutions are [tex]\pm 5i[/tex].

  • The problem is that such solutions are not true solutions because they require i.
  • Although the equation contains complex solutions, it is frequently stated that it has no answer.

Therefore, the final answer is "no solution".

Learn more about the quadratic function here:

brainly.com/question/4119784

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