Answer:
a)The volume is reduced to one-third of its original value.
Explanation:
For a gas at constant temperature, we can apply Boyle's law, which states that the product between pressure and volume is constant:
[tex]pV=const.[/tex]
where p is the pressure and V the volume.
In our case, this law can also be rewritten as
[tex]p_1 V_1 = p_2 V_2[/tex]
where the labels 1 and 2 refer to the initial and final conditions of the gas.
For the gas in the problem, the pressure of the gas is tripled, so
[tex]p_2 = 3p_1[/tex]
And re-arranging the equation we find what happens to the volume:
[tex]V_2 = \frac{p_1 V_1}{p_2}=\frac{p_1 V_1}{3p_1}=\frac{V_1}{3}[/tex]
so, the volume is reduced to 1/3 of its original value.
