Answer:
The area of the kite is [tex]42\ units^{2}[/tex]
Step-by-step explanation:
we know that
The area of a kite is half the product of the diagonals
so
[tex]A=\frac{1}{2}(D1*D2)[/tex]
we have
[tex]D1=2*(3)=6\ units[/tex]
Find the length side of diagonal D2
Applying the Pythagoras Theorem
[tex]D2=\sqrt{5^{2}-3^{2}} +10\\ \\D2=4+10\\ \\D2=14\ units[/tex]
Find the area of the kite
we have
[tex]D1=6\ units[/tex]
[tex]D2=14\ units[/tex]
substitute
[tex]A=\frac{1}{2}(D1*D2)[/tex]
[tex]A=\frac{1}{2}(6*14)=42\ units^{2}[/tex]
