Find the surface area of a cylinder with a height of 9 inches and base radius of 4 inches.

The surface area of the cylinder is 326.725 square inches if the height of 9 inches and base radius of 4 inches
In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.
We know the volume of the cylinder is given by:
[tex]\rm V = \pi r^2 h[/tex]
We have:
Height of the cylinder h = 9 inches
The radius r = 4 inches
SA = 2πr² + 2πrh
π = 3.14
SA = 2(3.14)(4)² + 2(3.14)(4)(9)
After calculating:
SA = 326.725 square inches
Thus, the surface area of the cylinder is 326.725 square inches if the height of 9 inches and base radius of 4 inches
Learn more about the cylinder here:
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