Answer:
[tex]1.63\cdot 10^{-24} J[/tex]
Explanation:
The energy of a photon is given by:
[tex]E=\frac{hc}{\lambda}[/tex]
where
h is the Planck constant
c is the speed of light
[tex]\lambda[/tex] is the wavelength of the photon
In this problem, we have a microwave photon with wavelength
[tex]\lambda=12.2 cm=0.122 m[/tex]
Substituting into the equation, we find its energy:
[tex]E=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{0.122 m}=1.63\cdot 10^{-24} J[/tex]
