Can anybody help me please I'm stuck with this question.

Find the perimeter of the polygon with vertices at (1, 3), (7, 3), (7, 7), and (4, 7).


22 units


13 units


18 units


20 units

Respuesta :

Answer: 18 units

Step-by-step explanation:since its is a horizontal line x2 - x1

7 -1 = 6

line 2:

since this is a vertical line y2 - y1

7 - 3 = 4

line 3:

since this is a horizontal line x2 - x1

7 - 4 = 3

line 4:

for this we need to use the distance formula which allows us to find the distance making a third point to form a right angle triangle

point 1: (1,3)

point 2: (4,7)

point 3 (new point) : (4,3)

now we can apply the pythogorean thereum (C squared = B squared + A squared) with the following lines.

line 1: (1,3) - (4,7)

line 2: (1,3) - (4,3)

line 3: (4,3) - (4,7)

line 1 squared = line2 squared + line 3 squared

calculate length of line 2 and 3

line 1 squared = (4 - 1) squared + (7 - 3) squared

line 1 squared = 3 squared + 4 squared

line 1 squared = 9 + 16

line 1 squared = 25

root both sides

line 1 = 5

add all the liens together

6 + 4 + 3 + 5 = 18