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Given circle assume that AB Is tangent to the circle and AD Passes through the center of the circle. If the circle has a radius of 5CM and AB is 6CM what is the length of the secant

Given circle assume that AB Is tangent to the circle and AD Passes through the center of the circle If the circle has a radius of 5CM and AB is 6CM what is the class=

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sqdancefan

Answer:

d. 2√34 cm

Step-by-step explanation:

Secant BD is the hypotenuse of right triangle ABD with legs given as AB = 6 cm and AD = 10 cm. Hence the Pythagorean theorem can be used to find BD:

BD = √(AB² +AD²) = √((6 cm)² +(10 cm)² = √136 cm = 2√34 cm