Answer:
[tex](-3, \frac{9}{5})[/tex]
Step-by-step explanation:
We have the equation [tex]2x + 5y-3 = 0[/tex].
The ordered pairs of this equation have the form [tex](x_0, y_0)[/tex]
Where x is the independent variable and y is the dependent variabe.
That is, the points belonging to the line [tex]2x + 5y-3 = 0[/tex] have the form [tex](x_0, f (x_0))[/tex]
For [tex]y = f(x)[/tex].
So, we need to find [tex]f(x_0)[/tex] for x_0 = -3.
Then we substitute x = -3 into the equation and clear the value of y.
[tex]2(-3) + 5y -3 = 0[/tex]
[tex]-6 + 5y = 3\\\\5y = 9\\\\y = \frac{9}{5}[/tex].
Then the ordered pair is:
[tex](-3, \frac{9}{5})[/tex]
