Answer:
The height of the cone is [tex]6.9\ units[/tex]
Step-by-step explanation:
we know that
The volume of the cone is equal to
[tex]V=\frac{1}{3}Bh[/tex]
where
B is the area of the circular base of the cone
h is the height of the cone
In this problem we have
[tex]V=29\ units^{3}[/tex]
[tex]r=2\ units[/tex]
Find the area of the base B
[tex]B=\pi r^{2}[/tex]
substitute the value of r
[tex]B=\pi (2)^{2}=4 \pi\ units^{2}[/tex]
Find the height of the cone
[tex]29=\frac{1}{3}(4 \pi)h[/tex]
[tex]h=29*3/(4 \pi)[/tex]
assume [tex]\pi=3.14[/tex]
[tex]h=29*3/(4*3.14)=6.9\ units[/tex]
