Point A(-7, -2) is rotated 270° counterclockwise and then shifted down 3 units. What are to coordinates of K’?

A. (2,4)

B. (-2, -7)

C. (-2, 4)

D. (7, -5)

Point A7 2 is rotated 270 counterclockwise and then shifted down 3 units What are to coordinates of K A 24 B 2 7 C 2 4 D 7 5 class=

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Answer:

C. (-2, 4)

Step-by-step explanation:

First we are going to rotate the point 270°; then we are going to shift it down 3 units.

Remember that the rule to rotate a point 270° counterclockwise about the origin is:

[tex]R_{270}(y,-x)[/tex]

In other words, we just need to switch the coordinates and change the sign of the second coordinate. Let's apply the rule to our point:

[tex]A = (-7, -2)[/tex]

[tex]A'=(y,-x)=(-2,--7)=(-2,7)[/tex]

Now we know that the coordinates of our point after the rotation are A' = (-2, 7)

The only thing left is shift that point 3 units down; to do it, we just need to subtract 3 from the y-coordinate:

[tex](x,y)-->(x,y-3)[/tex]

[tex]A'=(-2,7)[/tex]

[tex]K'=(-2,7-3)[/tex]

[tex]K'=(-2,4)[/tex]

We can conclude that after a rotation of 270° and a translation 3 units down, the coordinates of point K' are (-2, 4).

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