Answer:
150.8 J
Explanation:
The heat released by the copper wire is given by:
[tex]Q=mC_s \Delta T[/tex]
where:
m = 10.0 g is the mass of the wire
Cs = 0.377 j/(g.C) is the specific heat capacity of copper
[tex]\Delta T=40.0 C - 80.0 C=-40.0 C[/tex] is the change in temperature of the wire
Substituting into the equation, we find
[tex]Q=(10.0 g)(0.377 J/gC)(-40.0^{\circ})=-150.8 J[/tex]
And the sign is negative because the heat is released by the wire.
