A spinner has 6 equal sectors labeled A, B, C, D, E and F on it. The spinner is spun twice.

What is the probability of spinning B and then E, given that the spinner shows B on the first spin?

A. 1/2

B. 1/3

C. 1/6

D. 1/36

Respuesta :

Answer: C.  [tex]\dfrac{1}{6}[/tex]

Step-by-step explanation:

Given: A spinner has 6 equal sectors labeled A, B, C, D, E and F on it. The spinner is spun twice.

If it is given that the  spinner shows B on the first spin, then the total outcomes will be{ (B,A), (B,B), (B,C), (B,D), (B,E), (B,F)}=6

The number of favorable outcome = 1

Now, the probability of spinning B and then E, given that the spinner shows B on the first spin=[tex]\dfrac{1}{6}[/tex]

Answer: C. 1/6

Step-by-step explanation:

Ver imagen mibabiii