Answer:
584.4 g.
Explanation:
- Na₂CO₃ reacts with HCl according to the balanced reaction:
Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂.
It is clear that 1.0 mole of Na₂CO₃ reacts with HCl to produce 2.0 moles of NaCl.
Using cross multiplication:
1.0 mole of Na₂CO₃ → 2.0 moles of NaCl.
5.0 moles of Na₂CO₃ → ??? moles of NaCl.
The no. of moles of NaCl produced from 2.0 moles of Na₂CO₃ = (2.0 mol)(5.0 mol)/(1.0 mol) = 10.0 mol.
∴ The theoretical yield of NaCl = no. of moles of NaCl x molar mass of NaCl = (10.0 mol)(58.44 g/mol) = 584.4 g.
