Answer:
The position of ball is (0.78, 11.17) after 8 seconds.
Step-by-step explanation:
A bowling ball is rolled down the alley with a constant velocity of 1.4 m/sec at an angle of 86 degrees to the starting line.
Horizontal Position:
[tex]x=v\cos\theta \times t[/tex]
Vertical Position:
[tex]y=v\sin\theta \times t[/tex]
[tex]v=1.4\ m/s[/tex]
[tex]\theta=86^\circ[/tex]
[tex]t=8\ sec[/tex]
Substitute the value into formula
[tex]x=1.4\cos86^\circ \times 8[/tex]
[tex]x=0.78\ m[/tex]
[tex]y=1.4\sin86^\circ \times 8[/tex]
[tex]y=11.17\ m[/tex]
Hence, The position of ball is (0.78,11.17)
