Answer:
(C) 270
Step-by-step explanation:
Given: In the circle P, ∠TPB=90° and ∠TPC=128°.
To find: mTCB in circle P.
Solution: It is given that In the circle P, ∠TPB=90° and ∠TPC=128°, then
[tex]mTB+mTCB=360^{\circ}[/tex](sum of the minor and the major arc is 360°)
⇒[tex]90^{\circ}+mTCB=360^{\circ}[/tex]
⇒[tex]mTCB=360-90[/tex]
⇒[tex]mTCB=270^{\circ}[/tex]
Thus, the measure of arcTCB is 270°, hence option C is correct.
