Answer:
[tex]0.013 m^3[/tex]
Explanation:
The problem can be solved by using the ideal gas equation:
[tex]pV=nRT[/tex]
where
[tex]p=1.10 atm = 1.11\cdot 10^5 Pa[/tex] is the gas pressure
[tex]V[/tex] is the gas volume
n = 0.600 is the number of moles of the gas
[tex]R=8.314 J/(mol K)[/tex] is the gas constant
[tex]T=15.0^{\circ}+273.15=288.15 K[/tex] is the absolute temperature of the gas
Solving the equation for V, we find the volume of the gas:
[tex]V=\frac{nRT}{p}=\frac{(0.600 mol)(8.314 J/(mol K))(288.15 K)}{1.11\cdot 10^5 Pa}=0.013 m^3[/tex]
